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Question

If f(x) = [x] and g(x) = cos(πx), then the range of gof is.

A
{0}
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B
{-1, 1}
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C
{1, 0, 1}
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D
[1, 1]
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Solution

The correct option is B {-1, 1}
gof=g(f(x))=cos(πf(x))=cos(π[x])=cos( integral multiple of π)=1 or 1
Hence range of gof is {1,1}

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