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Question

If f(x)=x,g(x)=2x2+1 and h(x)=x+1 then (hogof)(x) is equal to

A
x2+2
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B
2x2+1
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C
x2+1
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D
2(x2+1)
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Solution

The correct option is D 2(x2+1)
Given f(x)=x,g(x)=2x2+1 and h(x)=x+1

hogof(x)

=h(g(f(x)))
=h(g(x))[f(x)=x]
=h(2x2+1)[g(x)=2x2+1]
=2x2+1+1
=2x2+2
=2(x2+1)
hogof(x)=2(x2+1)

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