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Question

If f(x)=[x]tan(πx) then f(k+) is equal to (where k is some integer and [.] denotes greatest integer function)

A
(k1)π(1)k
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B
kπ
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C
kπ(1)k
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D
(k1)π(1)k
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Solution

The correct option is A kπ
f(k+)=limh0+f(k+h)f(k)h

=limh0+[k+h]tan(kπ+πh)0h=limh0+kπ(tanπhπh)=kπ

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