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Question

If f(x)=xx2+1 & g(x)=max{f(t);0t<x}, then 10g(x)dx=?

A
2924
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B
76
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C
54
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D
none of these
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Solution

The correct option is A 2924
f(x)=xx2+1 & g(x)=max{f(t);0t<x}
y = g(x)
So, 10g(x)dx=1/20f(x)dx+[112]×54
=[x33+x22+x]1/20+58=2924

1112328_72599_ans_7b415e209b4d47cbb7e94781f6d9f217.jpg

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