If f(x+y)=f(x)f(y) and ∞∑x=1f(x)=2,x,y∈N, where N is the set of all natural numbers, then the value of f(4)f(2) is:
A
23
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B
19
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C
13
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D
49
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Solution
The correct option is D49 Let f(x)=ax
Given ∞∑x=1f(x)=2 ⇒a+a2+⋯+a∞=2
This is the case of Sum of infinite geometric progression ⇒a1−a=2 ⇒a=23 ⇒f(x)=(23)x
Thus f(4)f(2)=(23)4(23)2=49