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Question

If f(x+y)=f(x)+f(y). Then prove that f(x)=x.f(1)

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Solution


f(x+y)=f(x)+f(y)y=2:f(x)=f(x)+f(0)f(0)=0(x=1y=1);f(2)=2f(1)(x=2y=1);f(3)=2f(1)+f(1)=3f(1)f(x)=xf(1)

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