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Question

If f(xy1)=f(x)f(y)+f(x)y+1 and if f(0)=1, then f(x)=?

A
x1
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B
x+1
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C
x1
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D
x+1
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E
12x
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Solution

The correct option is A x+1
f(xy1)=f(x)f(y)+f(x)y+1
f(yx1)=f(y)f(x)+f(y)x+1
f(x)y=f(y)x
Put y=0; f(x)0=f(o)x
f(x)=1x

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