Question

If $F\left(y\right)=\log y$, then $F\left(y\right)+F\left(\frac{1}{y}\right)$ is equals to:

• A. 2
• B. 1
• C. 0
• D. -1

Answer 1

The correct option is C 0

$F\left(y\right)=\log yF\left(\frac{1}{y}\right)=\log \left(\frac{1}{y}\right)F\left(y\right)+F\left(\frac{1}{y}\right)=\log y+\log \left(\frac{1}{y}\right)=\log y+\log \left(1\right)-\log y=\log y+0-\log y=0$