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Multiple Bond Formation

If FeCl3.H2...

Question

If $F e C l_{3} . H_{2} O$ would be exist as a complex, one mole of it in aqueous solution on reaction with excess of $A g N O_{3}$ forms:

A

1 mole of

A g C l

(white precipitate)

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B

2 moles of

A g C l

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C

3 moles of

A g C l

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D

no reaction

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Solution

The correct option is A 1 mole of $A g C l$ (white precipitate)
The complex of $F e C l_{3} . H_{2} O$ in water can be represented as $[F e (H_{2} O)_{4} C l_{2}] C l .2 H_{2} O$ . It contains one chlorine in the ionization sphere.
It will react with 1 mole of silver nitrate to give one mole of silver chloride which is a white precipitate.

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Similar questions

Q. One mole of the complex with molecular formula

[C o (N H_{3})_{5} C l_{3}]

gives two moles of

A g C l

A g N O_{3}

. The complex is

[P t (N H_{3})_{5} C l] C l_{3}

is the true formula of the complex

P t C l_{4} \cdot 5 N H_{3}

. One mole of it on reaction with excess of

A g N O_{3}

yields three moles of white precipitate of

A g C l

.
If true enter 1, else enter 0.

One mole of the complex compound $C o (N H_{3})_{5} C l_{3}$ gives three moles of ions on dissolution in water. One mole of the same complex reacts with two moles of $A g N O_{3}$ solution to yield two moles of $A g C l (s)$ . The structure of complex is:

Q. In aqueous solution 1 mole of

C o C l_{3} .4 N H_{3}

gives 1 mole of AgCl precipitate with excess

A g N O_{3}

, then what is the secondary valency of metal?

P t C l_{4} .6 H_{2} O

on reaction with

A g N O_{3}

2

A g C l

(whit ppt) per mol of the

P t C l_{4} .6 H_{2} O

. The complex exists as

[P t C l_{2} (H_{2} O)_{4}] C l_{2} . 2 H_{2} O

.
If true enter 1, else enter 0.

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