If F eCl 3 is added to excess of hot waterA- Positive solution of F e 2 O 3- xH 2 O - F e 3- is formedB- Negative solution of F e 2 O 3 - F e OH 2-is formedC- Positive solution of F eO - F e 2- is formedD- Negative solution of F e 2 O 3- xH 2 O - OH -is formed

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Byju's Answer

Standard XII

Chemistry

Central Atom and Ligands

If F eCl 3 is...

Question

If $F e C l_{3}$ is added to excess of hot water

Positive solution of

F e O / F e^{2 +}

is formed

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Positive solution of

F e_{2} O_{3} . x H_{2} O / F e^{3 +}

is formed

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Negative solution of

F e_{2} O_{3} . x H_{2} O / O H^{-}

is formed

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Negative solution of

F e_{2} O_{3} / F e (O H)_{2}^{-}

is formed

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Solution

The correct option is B Positive solution of $F e_{2} O_{3} . x H_{2} O / F e^{3 +}$ is formed
If $F e C l_{3}$ is added to excess of hot water, a positively charged sol of hydrated ferric oxide is formed.
$F e_{2} O_{3} . x H_{2} O / F e^{3 +}$ .

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Similar questions

Q. A mixture of

F e O

and

F e_{2} O_{3}

is completely reacted with

100 m L

0.25 M

acidified

K M n O_{4}

solution. The resultant solution was then titrated with

Z n

dust which converted

F e^{3 +}

of the solution to

F e^{2 +}

.
The

F e^{2 +}

required

1000 m L

0.10 M

K_{2} C r_{2} O_{7}

solution. Find out the weight

% F e_{2} O_{3}

in the mixture.

Q. A mixture of

F e O

and

F e_{2} O_{3}

is completely reacted with

100 mL

0.25 M

acidified

K M n O 4

solution. The resultant solution was then titrated with

Z n

dust which converted the

F e^{3 +}

ions to

F e^{2 +}

ions. The

F e^{2 +}

ions required

1000 mL

0.10 M

K_{2} C r_{2} O_{7}

solution. Find out the weight percentage of

F e_{2} O_{3}

in the mixture.

Q. Which of the following options is/are true when 4 moles of

F e S O_{4}

is strongly heated?

Q. A

3.0 g

sample containing

F e_{3} O_{4}, F e_{2} O_{3}

and an inert impure substance is treated with excess of

K I

solution in presence of dilute

H_{2} S O_{4}

. The entire iron is converted to

F e^{2 +}

along with the liberation of iodine. The resulting solution is diluted to

100 m L

. A

20 m L

of the dilute solution requires

11.0 m L

0.5 M N a_{2} S_{2} O_{3}

solution to reduce the iodine present. A

50 m L

of the diluted solution after complete extraction of iodine requires

12.8 m L

0.25 M K M n O_{4}

solution in dilute

H_{2} S O_{4}

medium for oxidation of

F e^{2 +}

. Calculate the percentage of

F e_{2} O_{3}

and

F e_{3} O_{4}

in the original sample.

Q. A 5g sample containing

F e_{3} O_{4} (F e O + F e_{2} O_{3})

and an inert impurity is treated with excess of KI solution in the presence of dilute

H_{2} S O_{4}

. The entire iron converted to Ferrous ion along with the liberation of Iodine. The resulting solution is diluted to 100 mL. 20 mL of the diluted solution requires

10 m L o f 0.5 M N a_{2} S_{2} O_{3}

solution to reduce the iodine present. Calculate approximate percentage of

F e_{2} O_{3}

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If FeCl3 is added to excess of hot water

The correct option is B Positive solution of Fe2O3.xH2O/Fe3+ is formedIf FeCl3 is added to excess of hot water, a positively charged sol of hydrated ferric oxide is formed. Fe2O3.xH2O/Fe3+.

If $F e C l_{3}$ is added to excess of hot water

The correct option is B Positive solution of $F e_{2} O_{3} . x H_{2} O / F e^{3 +}$ is formed
If $F e C l_{3}$ is added to excess of hot water, a positively charged sol of hydrated ferric oxide is formed.
$F e_{2} O_{3} . x H_{2} O / F e^{3 +}$ .