Question

If first $100$ natural numbers are divided in groups of ten each, then the minimum number of primes are between:

• A. $1to10$
• B. $51to60$
• C. $81to90$
• D. $91to100$

Answer 1

The correct option is D

$91to100$

Explanation for the correct option:

Option (D) $91to100$

Prime number between $91to100$ is $97$. There is only one prime number. and thus it is the minimum number of prime number among the given options.

Explanation for the incorrect options:

Option (A) $1to10$

Prime numbers between $1to10$ are $2$, $3$, and $7$. There are only three prime numbers between $1to10$.

Option (B) $51to60$

Prime numbers between $51to60$ are $53$, and $59$. There are two prime numbers between $51to60$.

Option (C) $81to90$

Prime numbers between $81to90$ are $83$, and $89$. There are two three prime numbers between $81to90$

Hence, the correct answer is option (D) $91to100$