Question

If first term in $A.P$ is $\frac{1}{2}$ and the common difference is $\frac{1}{2}$ then its ${11}^{th}$ term is ________,

Answer 1

Given:-

First term of A.P. $\left(a\right)=\frac{1}{2}$

Common difference $\left(d\right)=\frac{1}{2}$

As we know that $n^{th}$ term of an A.P. is given as-

$a_n=a+(n-1)d$

Therefore,

$a_{11}=\frac{1}{2}+(11-1)\frac{1}{2}$

$\Rightarrow a_{11}=\frac{1}{2}+\frac{10}{2}=\frac{1+10}{2}=\frac{11}{2}$