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Question

If first term of an AP is 5, last term is 45 and the sum of the terms is 400, then the number of terms is

A
8
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B
10
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C
16
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D
20
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Solution

The correct option is C 16
As we know that sum of an A.P. is given as-
Sn=n2(a+l)
Where a and l are first term and last term respectively.
Given:-
Sn=400
a=5
l=45
n=?
Therefore,
400=n2(5+45)
400×2=n×50
n=80050=16

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