If five resistances, each of value 0.2 ohm, are connected in series, what will be the resultant resistance?
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Solution
If five resistors, each of value 0.2 Ω, are connected in series, the resultant resistance will be the sum of the individual resistances.
R = R1 + R2 + R3+ R4+ R5 R = 0.2 + 0.2 +0.2 + 0.2 + 0.2 R = 5 x 0.2 R = 1 Ω