If five resistances, each of value 0.2 ohm are connected in series, what will be the resultant resistance?

Open in App

Solution

If five resistances are connected in series and all are of 0.2 ohm then their resistances would be added.
So the ans would be,
(0.2+0.2+0.2+0.2+0.2) = 1 ohm
thus, the resultant resistance would be 1 ohm.

Suggest Corrections

Similar questions

2 o h m,

9 o h m .

\begin{matrix} The resultant resistance of n wires each of resistance r ohms is R, when they are connected in parallel. When these n resistances are connected in series, the resultant resistance will be :- \end{matrix}

Join BYJU'S Learning Program