If five times the fifth term of an A.P. is equal to 8 times its eighth term, show that its 13th term is zero.
Let a1, a2, a3..... an.... be the A.P. with its first term = a and common difference = d.
It is given that
5a5 = 8a8
⇒5(a+4d)=8(a+7d)
⇒5a+20d=8a+56d
⇒3a+36d=0
⇒3(a+12d)=0
⇒a+12d=0
⇒a+(13–1)d=0
⇒a13=0