Question

If following molecules undergo dimerization then find the value of $\frac{YZ}{X}$.
(i) $Cl{O}_3$, (ii) $OF$, (iii) $Ga{H}_3$, (iv) $AlC{l}_3$, (v) $IC{l}_3$, (vi) $Be{H}_2$, (vii) $N{O}_2$Where,
$X=$ Number of molecules which are hypervalent in dimeric form.
$Y=$ Number of molecules which com octet in dimer form.
$Z=$ Number of molecules which are hypovalent in dimeric form.

Answer 1

On formation of dimer,
$Cl{O}_3,IC{l}_3$ are hypervalent in dimeric form (X).

$OF,N{O}_2$ have completed their octet (Y).

$Ga{H}_3,AlC{l}_3,Be{H}_2$ are hypovalent in dimeric form.

Thus, $X=2,Y=2,Z=3$

$\frac{YZ}{X}=\frac{2\times 3}{2}=3$