Let, x 1+y +y 1+x =0.
Simplify the given equation.
x 1+y +y 1+x =0 x 1+y =−y 1+x
By squaring both sides of the above equation, we get,
x 2 ( 1+y )= y 2 ( 1+x ) x 2 + x 2 y= y 2 +x y 2 x 2 − y 2 =xy( y−x ) ( x+y )( x−y )=xy( y−x )
Further simplify the above equation.
( x+y )=−xy x+y+xy=0 y( 1+x )=−x y= −x ( 1+x )
Differentiate both sides with respect to x.
dy dx = d dx ( −x 1+x ) =−{ ( 1+x ) d dx ( x )−x d dx ( 1+x ) ( 1+x ) 2 } =− 1+x−x ( 1+x ) 2 dy dx =− 1 ( 1+x ) 2
Hence, it is proved that dy dx =− 1 ( 1+x ) 2 .