If for a conic section a focus is (−1,1), eccentricity =3 and the equation of the corresponding directrix is x−y+3=0 then the equation of the conic section is
A
7x2−18xy+7y2+50x−50y+77=0
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B
7x2+18xy+7y2=1
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C
7x2+18xy+7y2−50x+50y+77=0
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D
none of these
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Solution
The correct option is C7x2−18xy+7y2+50x−50y+77=0 Using definition of conic, PS2=e2.PM2 (x+1)2+(y−1)2=32∣∣∣x−y+3√2∣∣∣2 2(x2+y2+2x−2y+2)=9(x2+y2−2xy−6y+6x+9) 7x2−18xy+7y2+50x−50y+77=0