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Question

If for a conic section a focus is (1,1), eccentricity =3 and the equation of the corresponding directrix is xy+3=0 then the equation of the conic section is

A
7x218xy+7y2+50x50y+77=0
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B
7x2+18xy+7y2=1
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C
7x2+18xy+7y250x+50y+77=0
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D
none of these
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Solution

The correct option is C 7x218xy+7y2+50x50y+77=0
Using definition of conic, PS2=e2.PM2
(x+1)2+(y1)2=32xy+322
2(x2+y2+2x2y+2)=9(x2+y22xy6y+6x+9)
7x218xy+7y2+50x50y+77=0

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