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Question

If for a G.P. S3=31 and S6=3906 then find a

A
2
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B
3
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C
1
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D
4
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Solution

The correct option is C 1
Given, S3=31S3=a(r31)r1=31 ...(1)
and S6=3906S6=a(r61)r1=3906 ...(2)
Dividing (2) by (1), we get
r61r31=126
(r31)(r3+1)r31=126
r3+1=126
r3=125
r=5
Putting r=5 in (1), we get
a(531)51=31
31a=31
a=1
Hence a=1 and r=5.


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