If for a gas RCV-0-67- then themolecules of gas are

C_p C_V=R ...(i) & γ=CpC_V Given, RC_V=0.67 ⇒ nbsp; RC_V=C_p C_VC_V=0.67 Or, C_p C_VC_V=0.67 C_pC_V 1=0.67 ⇒C_pC_V=1.67 ∴γ=1.67 nbsp;Gas is monoatomi ...

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Standard XIII

Physics

Heat Capacity

If for a gas ...

Question

If for a gas $(\frac{R}{C_{V}}) = 0.67$ , then the
molecules of gas are

diatomic

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monoatomic

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triatomic

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polyatomic

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Solution

The correct option is B monoatomic
$C_{p} - C_{V} = R . . . (i)$
$& γ = \frac{C p}{C_{V}}$
Given, $\frac{R}{C_{V}} = 0.67$
$\Rightarrow \frac{R}{C_{V}} = \frac{C_{p} - C_{V}}{C_{V}} = 0.67$
Or, $\frac{C_{p} - C_{V}}{C_{V}} = 0.67$
$\frac{C_{p}}{C_{V}} - 1 = 0.67$
$\Rightarrow \frac{C_{p}}{C_{V}} = 1.67$
$∴ γ = 1.67$
Gas is monoatomic.

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If for a gas (RCV)=0.67, then the molecules of gas are

The correct option is B monoatomicCp−CV=R ...(i) & γ=CpCV Given, RCV=0.67 ⇒RCV=Cp−CVCV=0.67 Or, Cp−CVCV=0.67 CpCV−1=0.67 ⇒CpCV=1.67 ∴γ=1.67 Gas is monoatomic.

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