If for a sequence $(t_{n}), s_{n} = 4 n^{2} - 5 n$ , then the sequence is a G.P.

True

No worries! We‘ve got your back. Try BYJU‘S free classes today!

False

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B False
$S_{n} = 4 n^{2} - 5 n t_{1} = S_{1} = 4 - 5 = 1 t_{1} + t_{2} = S_{2} = 6 t_{2} = 7 t_{1} + t_{2} + t_{3} = S_{3} = 4 ({3)}^{2} - 5 (3) = 21 t_{3} = 15 t_{2} - t_{1} = t_{3} - t_{2} = 8$
Given sequence is a A.P. with common difference $8$

Suggest Corrections

Similar questions

(t_{n}), S_{n} = 4 n^{2} - 3 n

A . P .

(t_{n}), S_{n} = 2 n^{2} + 5 n,

t_{n}

T_{n} = 4 n^{2} - 1

T_{n} = 35

n

T_{n} = 5 n + 1

^{'} n^{'}

4 n^{2} + 5 n,

Join BYJU'S Learning Program