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Standard VI

Mathematics

Solution of an Equation

If for any ...

Question

If for any $A . P$ , $d = 5$ then $t_{18} - t_{13}$ =_________

5

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20

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25

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30

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Solution

The correct option is C $25$
It is given that,
$d = 5$
Now,
$t_{n} = a + (n - 1) d$
$t_{18} - t_{13} = (a + (18 - 1) d) - (a + (13 - 1) d)$
$(a + 17 d) - (a + 12 d)$
$= 5 d$
$= 5 (5)$
$= 25$

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Similar questions

Q. Choose the correct alternative answer for each of the following sub questions.
(1) The sequence –10, –6, –2, 2,...

(A) is an A.P., Reason d= –16	(B) is an A.P., Reason d= 4
(C) is an A.P., Reason d= –4	(D) is not an A.P.

(2) First four terms of an A.P. are ....., whose first term is –2 and common difference is –2.

(A) –2, 0, 2, 4	(B) –2, 4, –8, 16
(C) –2, –4, –6, –8	(D) –2, –4, –8, –16

(3) What is the sum of the first 30 natural numbers ?

(A) 464

(B) 465

(D) 461

(4) For an given A.P. t₇ = 4, d = –4, n = 101, then a = ....

(A) 6

(B) 7

(D) 28

(5) For an given A.P. a = 3.5, d = 0, n = 101, then t_n = ....

(A) 0

(B) 3.5

(D) 14.5

(6) In an A.P. first two terms are –3, 4 then 21^st term is ...

(A) –143

(B) 143

(D) 17

(7) If for any A.P. d = 5 then t₁₈ – t₁₃ = ....

(A) 5

(B) 20

(D) 30

(8) Sum of first five multuiples of 3 is...

(A) 45

(B) 55

(D) 75

(9) 15, 10, 5,... In this A.P sum of first 10 terms is...

(A) –75

(B) –125

(D) 125

(10) In an A.P. 1^st term is 1 and the last term is 20. The sum of all terms is = 399 then n = ....

T_{25} - T_{20} = 15

∴

d =

............. for the A.P.

Q. If in an A.P.,

T_{7} = 18, T_{18} = 7

,then find

T_{101}

Q. For A.P.

\frac{1}{3}, \frac{4}{3}, \frac{7}{3}, \frac{10}{3} . . . . . . .

Find

T_{18}

In the given figure, if $∠ A P D$ = (3x + 15)° and $∠ C P B$ = (4x - 5)°, then x = ___.

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If for any A.P , d=5 then t18−t13=_________

The correct option is C 25It is given that,d=5Now,tn=a+(n−1)dt18−t13=(a+(18−1)d)−(a+(13−1)d)(a+17d)−(a+12d)=5d=5(5)=25

If for any $A . P$ , $d = 5$ then $t_{18} - t_{13}$ =_________

The correct option is C $25$
It is given that,
$d = 5$
Now,
$t_{n} = a + (n - 1) d$
$t_{18} - t_{13} = (a + (18 - 1) d) - (a + (13 - 1) d)$
$(a + 17 d) - (a + 12 d)$
$= 5 d$
$= 5 (5)$
$= 25$