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Question

If for f (x) = λ x2 + μ x + 12, f' (4) = 15 and f' (2) = 11, then find λ and μ.

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Solution

f'x=λddxx2+μddxx+ddx12f'x=2λx+μ 1Given: f'4=152λ4+μ=15 From 18λ+μ=15 2Also, given: f'2=112λ2+μ=11 From 14λ+μ=11 3Subtracting equation (3) from equation (2):4λ=4λ=1Substituting this in equation (3):41+μ=11μ=7∴ λ=1 and μ=7

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