The correct option is A (2,−10,−2)
A(−1,2,1),B(−2,−1,−1)
[−−→AB →b1 →b2]=0
⇒∣∣
∣∣−1−3−22−11α5−α1∣∣
∣∣=0
⇒−1(−1+α−5)+3(2−α)−2(10−2α+α)=0
⇒6−α+6−3α+2α−20=0
⇒−8−2α=0
⇒α=−4
Checking Point satisfies L2
L2:x+2−4=y+19=z+11
Any point on L2 is (−4k−2,9k−1,k−1)
From given options, for point (2,−10,−2):
4−4=−99=−11
Therefore, option (a) is correct.