If for some x∈R, the frequrency distribution of the marks obtained by 20 students in a test is :
Marks
2
3
5
7
Frequency
(x+1)2
2x−5
x2−3x
x
then the mean of the marks is :
A
2.5
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B
3.2
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C
3.0
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D
2.8
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Solution
The correct option is D2.8 Total number of students =20 ⇒(x+1)2+2x−5+x2−3x+x=20⇒x2+x−12=0⇒(x−3)(x+4)=0⇒x=3 ∴ Mean of the marks =2(3+1)2+3(6−5)+5(9−9)+2120=2.8