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Question

If for the function f(x)=kx2+7x19, f'(5)=57, then the value of k is

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Solution

Givenf(x) = kx2+7x19and f'(5) = 57f'(x) = 2kx+7f'(5) = 2k(5)+757 = 10k+7k = 5


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