If for vectors a- and b- - a- -4- b- -3 and a-b- -8- then find - a-b-

| a × b |=| a || b |sinθ θ is the angle between two vectors given a . b =| a || b |cosθ ⟹ 8=4× 3× cosθ ⟹ cosθ = 2 / 3 ⟹ sinθ ...

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Vector Component

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Question

If for vectors $\to a$ and $\to b$ , $| \to a | = 4, ∣ ∣ \to b ∣ ∣ = 3$ and $\to a \to b = 8$ , then find $∣ ∣ \to a \times \to b ∣ ∣$ .

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\to A B = \to a, \to B C = \to b

\to A B = \to a, + \to b

\to B D = \to b, - \to a

∣ ∣ \to a - \to b ∣ ∣

\to a

\to b

| \to a | = 2, ∣ ∣ \to b ∣ ∣ = 3

\to a . \to b = 4

| \to a | = 2

| \to b | = 3

\to a \to b = 0

(\to a \times (\to a \times (\to a \times (\to a \times \to b))))

| \to a + \to b | = | \to a - \to b |

(\to a, \to b) = \frac{π}{2}

\to a, \to b, \to a + \to b

(\to a, \to b) = \frac{2 π}{3}

| \to a - \to b |

\to a

\to b

| \to a | = 2

| \to b | = 3

\to a . \to b = 4

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