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Question

If for x+ky +3z=0,3x+ky-2z=0,2x+3y-4z=0,there is no solution. then xyz-2 =?

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Solution

Here k = 16.5
we get k value by finding determinant and equating it with 0, which is the condition for no solution.

It is given that it has no solution. So x, y and z has no solution satisfying the given equation so it is not possible to find xyz^-2.

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