Question

If force, acceleration and time are taken as fundamental quantities, then the dimensions of length will be

• A. $F{T}^2$
• B. $F^{-1}{A}^2{T}^{-1}$
• C. $F{A}^{2}T$
• D. $A{T}^2$

Answer 1

Answer: (D)

$A{T}^2$

$F\equiv ML{T}^{-2}$

$A\equiv L{T}^{-2}$

$\Rightarrow L=A{T}^2$