If force and displacement of the particle (in direction of force) are doubled. Work should be:

Doubled

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4 times

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Halved

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1/4 times

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Solution

The correct option is B 4 times
Work done, $W = f o r c e \times d i s p l a c e m e n t = F d$
When force $F$ and displacement $d$ are doubled, the work done becomes, $W^{'} = (2 F) (2 d) = 4 F d = 4 W$

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If force and displacement of the particle (in direction of force) are doubled. Work should be:

The correct option is B 4 timesWork done, W=force×displacement=FdWhen force F and displacement d are doubled, the work done becomes, W′=(2F)(2d)=4Fd=4W

The correct option is B 4 times
Work done, $W = f o r c e \times d i s p l a c e m e n t = F d$
When force $F$ and displacement $d$ are doubled, the work done becomes, $W^{'} = (2 F) (2 d) = 4 F d = 4 W$