If force and length each be increased by four times, then the unit of work is increased by:

16 times

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8 times

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2 times

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4 times

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Solution

The correct option is A 16 times
we know,
$W = F \times S$ ,
initially $W_{1} = F_{1} \times S_{1}$
According to question force and distance increased by 4 times.
so, $W_{2} = 4 F_{1} \times 4 S_{1}$
$W_{2} = 16 (F_{1} \times S_{1})$
$W_{2} = 16 W_{1}$

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