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Question

If four numbers are in A.P. such that their sum is 50 and the greatest number is 4 times the least, then the numbers are:

A
5,10,15,20
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B
4,10,16,22
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C
3,7,11,15
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D
none of the above
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Solution

The correct option is A 5,10,15,20
Let the numbers be a3d,ad,a+d,a+3d
Given, sum of all the numbers:
a3d+ad+a+d+a+3d=50
4a=50
a=12.5
Given,
largest number = 4 (smallest number)
a+3d=4a12d
15d=3a
a=5d
d=12.55=2.5
Therefore, numbers are 5,10,15,20.

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