If four numbers are in A.P. such that their sum is 50 and the greatest number is 4 times the least, then the numbers are:
A
5,10,15,20
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B
4,10,16,22
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C
3,7,11,15
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D
none of the above
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Solution
The correct option is A5,10,15,20 Let the numbers be a−3d,a−d,a+d,a+3d Given, sum of all the numbers: a−3d+a−d+a+d+a+3d=50 4a=50 a=12.5 Given, largest number = 4 (smallest number) a+3d=4a−12d 15d=3a a=5d d=12.55=2.5 Therefore, numbers are 5,10,15,20.