If four numbers in A.P. are such that their sum is 50 and the greatest number is 4 times the least, then the numbers are
The correct option is C 5, 10, 15, 20
Let the four numbers in A.P. be as follows:
a−2d,a−d,a,a+d
Their sum = 50 (Given)
⇒(a−2d)+(a−d)+a+(a+d)=50
⇒2a−d=25……(i)
Also, (a+d)=4(a−2d)
⇒a+d=4a−8d
⇒3d=a……(ii)
From equations (i) and (ii), we get
d=5,a=15
Hence, the numbers are 15−10,15−5,15,15+5, i.e., 5,10,15,20.