wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If four numbers in A.P. are such that their sum is 50 and the greatest number is 4 times the least, then the numbers are


A

5, 10, 15, 20

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

4, 10, 16, 22

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

3, 7, 11, 15

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 5, 10, 15, 20

Let the four numbers in A.P. be as follows:

a2d,ad,a,a+d

Their sum = 50 (Given)

(a2d)+(ad)+a+(a+d)=50

2ad=25(i)

Also, (a+d)=4(a2d)

a+d=4a8d

3d=a(ii)

From equations (i) and (ii), we get

d=5,a=15

Hence, the numbers are 1510,155,15,15+5, i.e., 5,10,15,20.


flag
Suggest Corrections
thumbs-up
55
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Arithmetic Progression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon