If four resistors, each of the value 0.5 ohm are connected in series, then the total resistance of the circuit is

2 Ω

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4 Ω

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0.125 Ω

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5 Ω

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Solution

The correct option is A
2 Ω

Given:
resistance of each resistor = $0.5 Ω$
In series combination:

Equivalent resistance, $R_{e q} = R_{1} + R_{2} + R_{3} + R_{4}$

= 0.5 Ω + 0.5 Ω + 0.5 Ω + 0.5 Ω = 2 Ω
$R_{e q} = 2 Ω$

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If four resistors, each of the value 0.5 ohm are connected in series, then the total resistance of the circuit is

The correct option is A 2 Ω Given: resistance of each resistor = 0.5 Ω In series combination: Equivalent resistance, Req=R1+R2+R3+R4 = 0.5 Ω + 0.5 Ω + 0.5 Ω + 0.5 Ω = 2 Ω Req=2 Ω

The correct option is A
2 Ω

Given:
resistance of each resistor = $0.5 Ω$
In series combination:

Equivalent resistance, $R_{e q} = R_{1} + R_{2} + R_{3} + R_{4}$

= 0.5 Ω + 0.5 Ω + 0.5 Ω + 0.5 Ω = 2 Ω
$R_{e q} = 2 Ω$