If 1(1−yx)12 = 1+1kyx,find the value of k(x>>y)
1(1−yx)12 = (1−yx)−12
= 1+12(yx)
(Neglecting the higher powers)
⇒k = 2
If the pair of linear equations kx–y=5,x+ky=5 has a unique solution (x=2,y=1), then the value of k is ____.