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Question

If 1(x2+1x)43 can be expanded by binomial theorem if


A

x < 1

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B

|x| < 1

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C

x > 1

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D

|x| > 1

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Solution

The correct option is D

|x| > 1


The expansion is x83(1+1x3)43

Hence | 1x3| < 1 ⇒ |x| > 1


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