If 12q is a terminating decimal number, then which of the following is a possible value of q?
A
7
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B
9
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C
15
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D
21
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Solution
The correct option is C 15 127→ denominator = 7 129=43→ denominator = 3 1215=45→ denominator = 5 (of the form 2m×5n) 1221=47→ denominator = 7
Thus, among the given options, the only possible value of q that satisfies the given condition is 15.