If 3-5-7- - n terms -5-8-11- - - - -10 terms -7- the value of n is-

The correct option is A 35 3 + 5 + 7 + .........+ n terms = n/2(6 + (n 1)2) = n/2 (2n + 4) 5 + 8 + 11 + ..........+10 terms = 5(10 + 9×3) = 185 n(n+2)/185 = ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Sum of N Terms of an AP

If 3+5+7+…… ....

Question

If $\frac{3 + 5 + 7 + . . . . . . n t e r m s}{5 + 8 + 11 + . . . . . . . . . + 10 t e r m s}$ = 7, the value of n is:

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
35

3 + 5 + 7 + .........+ n terms = $\frac{n}{2}$ (6 + (n-1)2) = $\frac{n}{2}$ (2n + 4)

5 + 8 + 11 + ..........+10 terms = 5(10 + 9 $\times$ 3) = 185

$\frac{n (n + 2)}{185}$ = 7

$\Rightarrow$ n = 35

Suggest Corrections

Similar questions

Q. If

\frac{3 + 5 + 7 + . . . . . . + n (t e r m s)}{5 + 8 + 11 + . . . . . + 10 (t e r m s)} = 7

, then the value of

n

If $\frac{3 + 5 + 7 + . . . . . . . . + n t e r m s}{5 + 8 + 11 + . . . . . . . . + 10 t e r m s} = 7,$ the value of n is

Q. If

\frac{2 + 5 + 8 + . . . . . n t e r m s}{7 + 11 + 15 + . . . . . . . . n t e r m s} = \frac{23}{35}

, then n value is ___________?

Q. Given

P = 3 + 5 + 7 + . . . .

(

n

terms) and

Q = 5 + 8 + 11 + . . . . (10 terms)

. What is the value of

n

\frac{P}{Q} = 7

Q. If

\frac{2 + 5 + 8 + . . . . n t e r m s}{7 + 11 + 15 + . . . . . n t e r m s} = \frac{23}{35}

, then

n

value is ________.

Join BYJU'S Learning Program

If 3+5+7+......n terms5+8+11+.........+10 terms = 7, the value of n is:

The correct option is A 35 3 + 5 + 7 + .........+ n terms = n2(6 + (n-1)2) = n2 (2n + 4) 5 + 8 + 11 + ..........+10 terms = 5(10 + 9×3) = 185 n(n+2)185 = 7 ⇒ n = 35

If $\frac{3 + 5 + 7 + . . . . . . n t e r m s}{5 + 8 + 11 + . . . . . . . . . + 10 t e r m s}$ = 7, the value of n is:

The correct option is A
35

3 + 5 + 7 + .........+ n terms = $\frac{n}{2}$ (6 + (n-1)2) = $\frac{n}{2}$ (2n + 4)

5 + 8 + 11 + ..........+10 terms = 5(10 + 9 $\times$ 3) = 185

$\frac{n (n + 2)}{185}$ = 7

$\Rightarrow$ n = 35