Question

If $\frac{3}{5}$ of a number exceeds its $\frac{2}{7}$ by 44. Find the number.

Answer 1

Let number = 1

Then difference between $\frac{3}{5}\text{and}\frac{2}{7}$

$=\frac{3}{5}-\frac{2}{7}=\frac{21-10}{35}=\frac{11}{35}\therefore \frac{11}{35}\text{of a number}=44\therefore \text{Number}=44÷\frac{11}{35}=44\times \frac{35}{11}=\frac{1540}{11}=140Ans.$