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Question

If 3a5z3b5y=3a+5z3b+5y, prove that ab=zy.

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Solution

3a5z3b5y=3a+5z3b+5y

3a5z3a+5z=3b5y3b+5y [Applying alternendo] (1 Mark)

3a5z+3a+5z3a5z3a5z=3b5y+3b+5y3b5y3b5y [Applying componendo and dividendo] (1 Mark)

6a10z=6b10y

az=by

ab=zy [Applying alternendo] (1 Mark)


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