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Byju's Answer
Standard XII
Mathematics
f(x) Transforms to f(-x)
If a0/n+1+a...
Question
If
a
0
n
+
1
+
a
1
n
+
a
2
n
−
1
+
.
.
.
.
.
.
+
a
n
−
1
2
+
a
n
=
0
then
a
0
x
n
+
a
1
x
n
−
1
+
.
.
.
.
.
.
.
+
.
.
.
.
.
.
+
a
n
−
1
x
+
a
n
=
0
has
A
no solution in
(
0
,
1
)
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B
at least one solution in
(
0
,
1
)
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C
exactly one solution in
(
0
,
1
)
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D
at least one solution in
(
2
,
3
)
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Solution
The correct option is
B
at least one solution in
(
0
,
1
)
f
(
x
)
=
a
0
x
n
+
a
1
x
n
−
1
⋯
+
a
n
−
1
x
+
a
n
Let,
g
(
x
)
=
∫
x
0
f
(
x
)
=
a
0
x
n
+
1
n
+
1
+
a
1
x
n
n
…
a
n
−
1
x
2
2
+
a
n
x
g
′
(
x
)
=
f
(
x
)
g
(
x
)
is zero for
x
=
1
and
x
=
0
Therefore,
g
′
(
x
)
=
f
(
x
)
must be zero for at least one value between
0
and
1
Suggest Corrections
0
Similar questions
Q.
If
a
0
n
+
1
+
a
1
n
+
a
2
n
−
1
+
a
n
=
0
. Then the function
f
(
x
)
=
a
0
x
n
+
a
1
x
n
−
1
+
a
1
x
n
−
2
+
.
.
.
.
.
+
a
n
has in (0,1)
Q.
If
a
0
n
+
1
+
a
1
n
+
a
2
n
−
1
+
⋯
+
a
n
−
1
2
+
a
n
=
0
, then the equation
a
0
x
n
+
a
1
x
n
−
1
+
⋯
+
a
n
−
1
x
+
a
n
=
0
has, in the interval
(
0
,
1
)
Q.
In the polynomial
f
(
x
)
=
a
0
x
n
+
a
1
x
n
−
1
+
.
.
.
+
a
n
−
1
x
+
a
n
,
where
a
0
,
a
1
,
a
2
,
.
.
.
,
a
n
are the real numbers, if
a
0
=
a
1
=
a
2
=
.
.
.
=
a
n
−
1
=
0
and
a
n
≠
0
,
then this is
Q.
If
x
+
1
is a factor of
f
(
x
)
=
a
0
x
n
+
a
1
x
n
−
1
+
a
2
x
n
−
2
+
⋯
+
a
n
=
0
, then
Q.
If the polynomial equation
a
0
x
n
+
a
n
-
1
x
n
-
1
+
a
n
-
2
x
n
-
2
+
.
.
.
+
a
2
x
2
+
a
1
x
+
a
0
=
0
n positive integer, has two different real roots α and β, then between α and β, the equation
n
a
n
x
n
-
1
+
n
-
1
a
n
-
1
x
n
-
2
+
.
.
.
+
a
1
=
0
has
(a) exactly one root
(b) almost one root
(c) at least one root
(d) no root
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