Question

If $\frac{a+b}{a-b}$ = $\frac{9}{13}$

Find the value of $\frac{a}{b}$

• A. $\frac{2}{11}$
• B. $\frac{22}{11}$
• C. $\frac{11}{2}$
• D. $\frac{13}{9}$

Answer 1

Answer: (C), (D)

The correct options are
C

$\frac{11}{2}$

D

$\frac{13}{9}$

$\frac{a+b}{a-b}$ = $\frac{9}{13}$

we know if $\frac{a}{b}$ = $\frac{c}{d}$

then $\frac{a+b}{a-b}$ = $\frac{c+d}{c-d}$

Hence $\frac{a+b+a-b}{a+b-a+b}=\frac{9+13}{9-13}$

$\frac{2a}{-2b}=\frac{22}{-4}$

- $\frac{2\left(a\right)}{2\left(b\right)}=-\frac{11}{2}$

$\frac{a}{b}=\frac{11}{2}$