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Question

If ab+ba=1, then a3+b3=


A

1

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B

-1

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C

12

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D

0

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Solution

The correct option is D

0


ab+ba=1 a2+b2ab=1 a2+b2=abNow, a3+b3=(a+b)(a2ab+b2)=(a+b)(a2+b2ab)=(a+b)(abab)=(a+b)×0=0


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