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Question

If ab = cd, then

which of the following statement is true?


A

ab = a+ncb+nd

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B

ab < a+ncb+nd

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C

ab > a+ncb+nd

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D

acbd =1

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Solution

The correct option is A

ab = a+ncb+nd


We have

If ab = cd

then we know ad = bc

a( b + nd) = ab + nad

b(a + nc) = ab + nbc

We have ad = bc

nad = nbc

Hence a(b+nd = b(a+nc)

ab = b+nda+nc


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