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Question

If log2(4x2āˆ’xāˆ’1)log2(x2+1)>1 then x lies in the interval


A
(,2/3)
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B
(1,)
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C
(2/3,0)
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D
None of these
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Solution

The correct option is B (1,)

log2(4x2x1)log2(x2+1)>04x2x1x2+1>13x2x2>0(3x+2)(x1)>0x<2/3 or x>1


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