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Question

If logxa=logy2=logz5=kandx4y3z2=1, find 'a'

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Solution

logx=ak,x=eak

Similarly y=e2k

z=e5k

(eak)4(e2k)3(e5k)2=1

e10ak10ak=e0, which is always equal to 1 irrespective of value of 'a'

a(,)

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