If p-q- 2-3 2 - 6-7 0 then the value of q-p 3 is

P/q= ( 2/3 )^2 ÷ ( 6/7 )^0 = ( 2/3 )^2 ÷ 1 (∵ a^0=1) ⇒p/q=4/9 ⇒q/p=9/4 ⇒ ( q/p )^3 = ( 9/4 )^3=729/64 ...

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Relation between Roots and Coefficients for Quadratic

If p/q= 2/3 2...

Question

If $\frac{p}{q} = {(\frac{2}{3})}^{2} \div {(\frac{6}{7})}^{0}$ then the value of ${(\frac{q}{p})}^{3}$ is

$\frac{54}{28}$

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$\frac{64}{729}$

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$\frac{28}{54}$

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$\frac{729}{64}$

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Solution

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Similar questions

\frac{p}{q} = {(\frac{2}{3})}^{2} \div {(\frac{6}{7})}^{0}

{(\frac{q}{p})}^{3}

If $\frac{p}{q} = {(\frac{2}{3})}^{2} \div {(\frac{6}{7})}^{0}$ then the value of ${(\frac{q}{p})}^{3}$ is-

\frac{p}{q} = {(\frac{2}{3})}^{2} \div {(\frac{6}{7})}^{0}

{(\frac{q}{p})}^{3}

If $\frac{p}{q} = {(\frac{2}{3})}^{2} \div {(\frac{6}{7})}^{0}$ then the value of ${(\frac{q}{p})}^{3}$ is

\frac{p}{q} = {(\frac{3}{2})}^{- 2} \div {(\frac{6}{7})}^{0}

{(\frac{p}{q})}^{- 3}

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