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Question

If sin4Aa+cos4Ab=1a+b, then the value of sin8Aa3+cos8Ab3 is equal to

A
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B
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C
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D
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Solution

The correct option is A

(a) It is given that sin4Aa+cos4Ab=1a+b

(1cos2A)24a+(1+cos2A)24b=1a+b

b(a+b)(12cos2A+cos22A)+a(a+b)(1+2cos2A+cos22A)=4ab

{b(a+b)+a(a+b)}cos22A+2(a+b)(ab)cos2A


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