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Question

If T2T3 in the expansion of (a+b)n and T3T4 in the expansion of (a+b)n+3 are equal, then n =


A

3

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B

4

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C

5

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D

6

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Solution

The correct option is C

5


In (a+b)n in T2T3 = nC1an1bnC2an2b2 = 2a(n1)b and (a+b)n+3 T3T4 = n+3C2an+1b2n+3C3anb3 = 3a(n+1)b

If these are equal then 2a(n1)b = 3a(n+1)b so n = 5


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